Question

plz plz help me guys

find the value of x where root(x+3) + root(x-2) = 5
plz plz help me​

Answer 1

Answer:

x = 6

Step-by-step explanation:

Equation is √(x + 3) + √(x - 2) = 5

=> √x + 3 = 5 - √(x - 2)

Squaring both sides, we will get

=> (√x + 3)² = (5 - √x - 2)²

=> x + 3 = x + 23 - 10√x - 2

=> 3 = -10√x - 2 + 23

=> -20 = -10√x - 2

Squaring on both sides.

=> (-20)² = (-10√x - 2)²

=> 400 = 100x - 200

=> 400 + 200 = 600x

=> x = 6

Hence, the value of x = 6.

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Answer 2

$\sqrt{x + 3} \ + \sqrt{x - 2} = 5 \\ x + 3 + x - 2 = {5}^{2} \\ 2x + 1 = 25 \\ 2x = 25 - 1 \\ x = 24 \div 2 \\ x = 12$

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