Math, asked by aarushi47, 1 year ago

plz plz help me plz plz plz plz plz plz plz!

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Answers

Answered by sumanththescientist
1
12)n/2[2a+(n-1)d]
10[2+19(3)]=590

aarushi47: slove this plz
Answered by Sonalisingh12
1
11) a5 + a6= 74
a+4d+a+5d=74
2a+9d=74 -----(1)

a4+a2=44
a+3d+a+d=44
2a+4d=44----(2)
subtracting (1) and (2)
5d=30
d=6
putting d=6 in equation (2)
2a+4*6=44
2a+24=44
2a=20
a=10 (therefore AP is 10,16,22....)

12) a=1,n=20,d=3
Sn=n/2[2a+(n-1)d]
=20/2[2*1+(20-1)3]
=10[2+19*3]
=10[2+57]
=10*59
590


aarushi47: slove the sum and show me
Sonalisingh12: ok
aarushi47: fast pls
Sonalisingh12: hey I solved the problem
Sonalisingh12: can you please mark me as brainliest
Sonalisingh12: thanks
aarushi47: welcome
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