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A girl of mass 40 kgs jumps with a horizontal velocity of 5m/s onto a stationary cart of 3kg with frictionless wheels . What is her velocity as the cart starts moving?
Assume that there is no external unbalanced force acting in the horizontal direction .
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Answered by
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bonjour dear!
no external force → momentum is constant
momentum of girl ⇒ 40 × 5 = 200 kg -m/sec
momentum of girl and cart = total momentum of the girl + momentum of cart
= 200 +0
= 200 kg m/sec
speed = 200/(40+3)
= 200/43
= 4.65 m/sec
hope this helps
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vedang13122003:
helped me too much
Answered by
1
no external force => momentum is constant.
momentum of girl = 40 * 5 = 200 kg-m/sec
momentum of girl and cart = total momentum of the girl + momentum of cart
= 200 + 0 = 200 kg m/sec
speed = 200 / (40 + 3)
= 4.65 m/sec
hope answer helped you please mark me brainliest
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