Question

plz plz plz, answer this question:
Find and correct the errors in the following statement.
[3x+2]² = 3x²+ 6x + 4​

Answer 1

$( {3x + 2)}^{2} = 3 {x}^{2} + 6x + 4 \\ (a + {b)}^{2} = {a}^{2} + {b}^{2} + 2ab$

$( {3x + 2)}^{2} = 3 {x}^{2} + 4 + 12x$

$({3x + 2)}^{2} = 3{x}^{2} + 12x + 4$

Answer 2

$\sf\huge\bold{\underline{\underline{{Solution}}}}$

How to solve:

step1:First step is to open the brackets and expanding the terms.

Step2:Make Variable terms and constant terms together.

Step3: Evaluate it as you can.

[3x+2]²=3x²+6x+4

Here, [ 3x+2]² is in the form of (a+b)²

Identity used here

(a+b)²=a²+b²+2ab

➝ (3x)²+(2)²+2(3x)(2) = 3x²+6x+4

Expanding the terms :

➝9x²+4+12x= 3x²+6x+4

solving for x²

➝9x²-3x²+12x+4= 6x+4

➝6x²+12x+4=6x+4

solving for x

➝6x²+12x-6x+4=4

➝6x²+6x+4=4

Since ,4 lies on both sides so,it gets automatically cancelled.

➝6x²+6x

Taking 6x as common

➝6x(x+1)