Question

plz plz plz give me answer on paper and send me plz OK fast plz plz plz OK fast plz plz plz OK


plz fast OK

Answer 1

$\huge\bold\green{Solution :\longrightarrow}$

Total weight of the sweets

$\mathfrak{ = (2 \frac{7}{8} + 3 \frac{1}{4} ) }\: \mathsf{kg}$

$\mathfrak{ = ( \frac{23}{8} + \frac{13}{4} )} \: \mathsf{kg}$

$\mathfrak{= ( \frac{23 + 26}{8} )} \: \mathsf{kg}$

$\mathfrak{ = \frac{49}{8}} \: \mathsf{kg}$

$\mathfrak{= 6 \frac{1}{8}} \: \mathsf{kg}$

Answer 2

Hope U Understand dear...