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Step-by-step explanation:
if angle ABC =angle BCD(alternate angles) then AB||CD, so we can see clearly that 40°=20°+20° hence AB||CD, so (a) part is done
if angle ECD+angle CEF=180°(angles on same side of transverse are Supplementary) then EF||CD so,
clearly we see 160°+20°=180° hence EF||CD
now, as AB||CD
EF||CD
=>AB||EF
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