Question

plz plz plz.. I beg you
...
factorise..

x³-x²+ax+x-a-1...
god will bless you I am beginner in factorization

Ans=(x-1)(x²+a+1)​

Answer 1

QUESTION :-

Factorize :- $x^3 - x^2 + ax + x - a - 1$

SOLUTION :-

By Grouping the Terms, we get -

$\Rightarrow x^3 - x^2 + ax + x - a - 1 = \bold {(x^3 + ax + x) + (-x^2 - a - 1)}$

Pick out the Common Factors - x in the First and (-1) in the Second

$\Rightarrow x (x^2 + a + 1) -1 (x^2 + a + 1)$

So, Factor out the Common Term $(x^2 + a + 1)$ and By the Distributive Law, we get the Answer as :-

$= \bold {(x^2 + a + 1)(x - 1)}$

Hence, it is also equal to the Answer that you've stated in the Question...

CONCLUSION :-

The Factorized Form of $x^3 - x^2 + ax + x - a - 1$ is = $\bold {(x^2 + a + 1)(x - 1)}$

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Answer 2

Answer:

x^3 - x^2 + x - a - 1

= (x^3 - x^2) + (ax - a) + (x-1)

= x^2 (x - 1) + a(x - 1) + 1(x - 1)

= (x - 1) (x^2 + a + 1) [Taking x - 1 common]

Ans: x^3 - x^2 + ax + x - a - 1 = (x - 1) ( x^2 + a + 1)

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