Math, asked by itzTabsum, 10 months ago

plz plz plz plz answer this question​

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Answered by madanlal166063
1

Answer:

I think this is answer

Step-by-step explanation:

please give me mark

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Answered by apm43
0

 \mathfrak \blue{here \: is \: your \: answer} \\ \mathfrak{p(x) = 2x + 1} \\ \mathfrak{p( -  \frac {1 }{2} }) = 2( -  \frac{1}{2} ) + 1 \\ p( -  \frac{1}{2} ) =  -  \frac{2}{2}  + 1 \\ p( -  \frac{1}{2} ) =  - 1 + 1 \\ p( -  \frac{1}{2} ) = 0 \\ so... -  \frac{1}{2}  \: is \: zero \: of \: the \: above \: equation

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