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Step-by-step explanation:
Area=l×b=600.......eq.1
perimeter=2(l+b)=100
l+b=50.......eq.2
l=50-b.....eq.3
put the value of l in eq. 1
(50-b)×b=600
50b-b^2=600
b^2-50b+600=0
b^2-30b-20b+600=0
b(b-30)-20(b-30)=0
(b-30)(b-20)=0
b=30 or 20.
putting the value of b in eq. 3, we get
when b=30
l=50-30=20
when b=20
l=50-20=30
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