Question

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(FROM THE PICTURE)​

Answer 1

Given :

➳ Height of tower (H) = 100m

➳ Body is stopped after 2s and then instantaneously released.

To Find :

➾ Height of body after next 3s.

Solution :

➨ Here, acceleration due to gravity continuously acts in downward direction.

➨ For a free falling object, g is taken positive.

✴ Distance covered in first 2s :

⇒ d = ut + (1/2)gt²

⇒ d = 0 + (1/2)(10 × 2²)

⇒ d = 0.5 × 40

⇒ d = 20m

✭ Height of body after 2s :

➝ x = H - d

➝ x = 100 - 20

➝ x = 80m

✴ Distance covered in next 3s :

⇒ d' = ut' + (1/2)gt'²

⇒ d' = 0 + (1/2)(10 × 3²)

⇒ d' = 0.5 × 90

⇒ d' = 45m

✭ Height of body from ground :

➝ H' = x - d'

➝ H' = 80 - 45

➝ H' = 35m