Question

Plz Plz plz plz solve this maths.........


plz plz​

Answer 1

Answer:

Option (C) 138 $cm^{2}$ is the correct answer.

Step-by-step explanation:

Area ΔADF = $\frac{1}{2}$ x DF x AD = $\frac{1}{2}$ x 12 x 15 = 90 $cm^{2}$

Area ΔCEF = $\frac{1}{2}$ x CF x CE = $\frac{1}{2}$ x (24 - 12) x 8 = 48 $cm^{2}$

Area ΔABE = $\frac{1}{2}$ x AB x BE = $\frac{1}{2}$ x 24 x (15 - 8) = 84 $cm^{2}$

Area of the shaded region:

= Area ΔAEF

= Area of Rectangle ABCD - Area ΔADF - Area ΔCEF - Area ΔABE

= 24 x 15 $cm^{2}$ - (90 + 48 + 84) $cm^{2}$ = (360 - 222) $cm^{2}$ = 138 $cm^{2}$