plz plz plz solve this 2problem
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1.draw a line of 10.7 =9.7+1 cm
2.the point where u marked now construct the perpendicular bisector of the line and then using the centre draw the semicircle.
3.the point where u marked the line segment till 9.7 cm draw a straight line touching the semicircle vertically.
4 now draw the line joining the centre from the point of vertical line when it touches the semicircle.(a triangle will be formed)
5.take the compass and. measure the length of hypo. and use it to draw the arc from the point where it touches semicircle. till it touches the plane
6.now extend 10.7 cm line further the point where arc intersects the plane is ur √9.7
(a+b)^3 - 8(a-b)^3
a^3 + b^3 +3a^2b +3ab^2 -8(a^3-b^3-3a^b+3ab^2)
a^3 + b^3 +3a^2b +3ab^2-8a^3+8b^3+24a^b-24ab^2
a^3-8a^3+ b^3+8b^3+3a^2b+24a^b+3ab^2-24ab^2
5a^3+9b^3+27a^2b-21ab^2
hope it helps u mate...
pls mark me brainliest
2.the point where u marked now construct the perpendicular bisector of the line and then using the centre draw the semicircle.
3.the point where u marked the line segment till 9.7 cm draw a straight line touching the semicircle vertically.
4 now draw the line joining the centre from the point of vertical line when it touches the semicircle.(a triangle will be formed)
5.take the compass and. measure the length of hypo. and use it to draw the arc from the point where it touches semicircle. till it touches the plane
6.now extend 10.7 cm line further the point where arc intersects the plane is ur √9.7
(a+b)^3 - 8(a-b)^3
a^3 + b^3 +3a^2b +3ab^2 -8(a^3-b^3-3a^b+3ab^2)
a^3 + b^3 +3a^2b +3ab^2-8a^3+8b^3+24a^b-24ab^2
a^3-8a^3+ b^3+8b^3+3a^2b+24a^b+3ab^2-24ab^2
5a^3+9b^3+27a^2b-21ab^2
hope it helps u mate...
pls mark me brainliest
gamingbeast29:
me - nanded city pune
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