Question

Plz.... Plz.... Plz.... Solve this question 5,6 with solution plzzzzzzzzzzzzzzzz

Answer 1

Answer:

(5) 77 m²

(6) 3465 m²

Step-by-step explanation:

(5)

Given that at the top and bottom, 25 cm of the pillar is covered.

Area to be covered = 25 + 25

                                 = 50 cm

                                 = 0.5 m.

Height of the pillar = 7.5 m.

Diameter of the pillar = 3.5 m.

Then, radius = 1.75

Remaining portion = 7.5 - 0.5

                               = 7 m.

∴ Area of the pillar = 2πrh

                               = 2 * (22/7) * 1.75 * 7

                               = 77 m²

Therefore, Area of the pillar = 77 m².

(6)

Given,Diameter = 98 cm.

Then,radius = 49 cm.

Length(h) = 1.25 m.

Note: In one revolution the wheel of the roller will cover an area of CSA.

∴ Curved surface area of roller = 2πrh

                                                     = 2 * (22/7) * 0.49 * 1.25

                                                    = 3.85 m²    

Area leveled by roller in 1 revolution = 3.85 m².

In 900 revolutions, Area of the road covered:

= (900 * 3.85)

= 3465 m².

Therefore, Area of the road = 3465 m².

Hope it helps!