Question

plz plz plZ tell the answer ​

Answer 1

Answer:

given above

Step-by-step explanation:

have a look in that picture.

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Answer 2

Answer:

θ = 60°

Step-by-step explanation:

given , $\frac{cos\theta - sin\theta}{cos\theta + sin\theta}$ = $\frac{1-\sqrt{3} }{1+\sqrt{3}}$

consider, LHS = $\frac{cos\theta - sin\theta}{cos\theta + sin\theta}$

= $\frac{cos\theta(1- \frac{sin\theta}{cos\theta} ) }{cos\theta(1+ \frac{sin\theta}{cos\theta} )}$

= $\frac{cos\theta(1- tan\theta) }{cos\theta(1+ tan\theta)}$

= $\frac{1- tan\theta}{1+ tan\theta}$

comparing the deduced value with the RHS,

ie., $\frac{1- tan\theta}{1+ tan\theta}$ = $\frac{1- \sqrt{3}}{1+ \sqrt{3}}$

=> tanθ = √3  

=> θ = tan⁻¹(√3)

=> θ = 60°