Question

Plz plz solve it. .​

Answer 1

Step-by-step explanation:

given,

A={0,2,3,4,6,7} and B={1,3,4,5}

THEN,

A-B={0,2,6,7}

B-A={1,5}

therefore,

(A-B)U(B-A)={0,2,6,7,1,5}

A U B ={0,2,3,4,6,7}U{1,3,4,5}

A U B ={0,1,2,3,4,5,6,7}

A intersection B= {0,2,3,4,6,7}intersection{1,3,4,5}

A intersection B={3,4}

therefore,

(A U B)-(A intersection B)= {0,1,2,3,4,5,6,7}-{3,4}

={0,1,2,5,6,7}

WE CAN NOTICE THAT (A-B) U(B-A),(A U B)-(A INTERSECTION B) ARE SAME.

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Answer 2

Answer:

Given that

A={0,2,3,4,6,7}

and

B={1,3,4,5}

Now,

[i](A-B)U(B-A)

[i](A-B)U(B-A) = [{0,2,6,7}]U[{1,5}]

[i](A-B)U(B-A) = [{0,2,6,7}]U[{1,5}]= {0,1,2,4,6,7}

And))

[ii] (A U B )-(A n B)

[ii] (A U B )-(A n B)=[{ 0, 1, 2, 3, 4, 5, 6, 7}][{ 3, 4}]

[ii] (A U B )-(A n B)=[{ 0, 1, 2, 3, 4, 5, 6, 7}][{ 3, 4}]={ 0, 1, 2, 5, 6, 7}.

After finding these two we noticed that both

(A-B)U(B-A) and (A U B )-(A n B) are equals to each other .