CBSE BOARD X, asked by guri57, 1 year ago

plz plz solve it . i will mark u brainlist.

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hrushi2000: Explanation:

1−sinx1+sinx=(secx−tanx)2

Left Side : =1−sinx1+sinx

=1−sinx1+sinx⋅1−sinx1−sinx

=1−2sinx+sin2x1−sin2x

=1−2sinx+sin2xcos2x

=1cos2x−2sinxcos2x+sin2xcos2x

=1cos2x−2⋅1cosxsinxcosx+sin2xcos2x

=sec2x−2secxtanx+tan2x

=(secx−tanx)(secx−tanx)

=(secx−tanx)2

∴= Right Side

this one is the right answer sorry for inconvenience
Anonymous: no problem :-)
guri57: i know she did little mistake .....but i got it
guri57: nd i got right answer
Anonymous: thx for brainliest :-)
hrushi2000: ignore those wrong symbols and start reading from = symbol
hrushi2000: ok

Answers

Answered by hrushi2000
0
Explanation:

1+sinx1−sinx=(secx+tanx)2

Right Side =(secx+tanx)2

=(secx+tanx)(secx+tanx)

=sec2x+2secxtanx+tan2x

=1cos2x+2⋅1cosx⋅sinxcosx+sin2xcos2x

=1+2sinx+sin2xcos2x

=(1+sinx)(1+sinx)1−sin2x

=(1+sinx)(1+sinx)(1+sinx)(1−sinx)

=1+sinx1−sinx

= Left Side

Answered by Anonymous
5
➡Hey !!

➡ Refer to the attachment please !!
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