plz plz solve it . i will mark u brainlist.
Attachments:

Answers
Answered by
0
Explanation:
1+sinx1−sinx=(secx+tanx)2
Right Side =(secx+tanx)2
=(secx+tanx)(secx+tanx)
=sec2x+2secxtanx+tan2x
=1cos2x+2⋅1cosx⋅sinxcosx+sin2xcos2x
=1+2sinx+sin2xcos2x
=(1+sinx)(1+sinx)1−sin2x
=(1+sinx)(1+sinx)(1+sinx)(1−sinx)
=1+sinx1−sinx
= Left Side
1+sinx1−sinx=(secx+tanx)2
Right Side =(secx+tanx)2
=(secx+tanx)(secx+tanx)
=sec2x+2secxtanx+tan2x
=1cos2x+2⋅1cosx⋅sinxcosx+sin2xcos2x
=1+2sinx+sin2xcos2x
=(1+sinx)(1+sinx)1−sin2x
=(1+sinx)(1+sinx)(1+sinx)(1−sinx)
=1+sinx1−sinx
= Left Side
Answered by
5
➡Hey !!
➡ Refer to the attachment please !!
___________________________________
➡ Refer to the attachment please !!
___________________________________
Attachments:

Similar questions
1−sinx1+sinx=(secx−tanx)2
Left Side : =1−sinx1+sinx
=1−sinx1+sinx⋅1−sinx1−sinx
=1−2sinx+sin2x1−sin2x
=1−2sinx+sin2xcos2x
=1cos2x−2sinxcos2x+sin2xcos2x
=1cos2x−2⋅1cosxsinxcosx+sin2xcos2x
=sec2x−2secxtanx+tan2x
=(secx−tanx)(secx−tanx)
=(secx−tanx)2
∴= Right Side
this one is the right answer sorry for inconvenience