Question

plz plz solve question 27

Answer 1

since AE parallel to BD, then

x=y (Alt.Int.Angles),

also BED will be isosceles triangle,

then

angle BED=angle BDE=z,

since each angle of a regular pentagon=108°,

then
angle AEB+angle BED=108°,

x+z=108°,

Now, in ∆BED


angle BED+angle BDE+angle DBE=180°,

z+z+y=180°,

z+z+x=180°,

z+108°=180°,

then

z=180°-108°,

z=72°,

then

x+z=108°,

x+72°=108°,

x=108°-72°,

x=36°,


then

y=x=36°