Question

Plz plz solve this problem...​

Answer 1

solution :

Here ,

Given, speed of bullet (u)= 40m/s

Angle = 30 °

we have to find,

maximum height =?

time of flight=?

Horizontal range=?

g=10m/s-2

we have ,

Maximum height =u2sinsquare30°/2g

=(40×40×1/4)÷2×10

=400÷20

=20 m

2.time of flight =2usin30°/g

=2×40×1/2 ÷10

=40/10

= 4 second

3.horizontal range =u2 sin2¤/g

=1600×sin60/10

= 160×1.2247

=195.95m