plz plz solve this sum for me
Attachments:
Answers
Answered by
0
The perimeter of the rectangle is 2(l+b)
=2(40+22)
=2*62
=124
Now, the perimeter of rectangle=Perimeter of square
Perimeter of square=4a
124=4a
a=124÷4
a=31cm
So, the measure of each side is 31 cm.
Area of rectangle=l*b
=40*22
=880cm^2
And, Area of square formed=a^2
=31^2
=961 cm^2
Hence, the shape which enclosed more area is square with area 961 cm^2
=2(40+22)
=2*62
=124
Now, the perimeter of rectangle=Perimeter of square
Perimeter of square=4a
124=4a
a=124÷4
a=31cm
So, the measure of each side is 31 cm.
Area of rectangle=l*b
=40*22
=880cm^2
And, Area of square formed=a^2
=31^2
=961 cm^2
Hence, the shape which enclosed more area is square with area 961 cm^2
muskaneharshita2111:
Please mark me as brainliest..... Please please.....
Similar questions