plz plz tell this question step by step
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Rationalize 1st fraction, by multiplying (√2 - √3) in both Numerator & Denominator.
→√6(√2 - √3)/((√2)² - (√3)²)
→ (√12 - √18)/(-1)
→ -(2√3 - 3√2)
→ (3√2 - 2√3)
Now rationalize 2nd fraction, by multiplying (√6 - √3) in both Numerator & Denominator, we get:
→ 3(√6 - √3)/ ((√6)² - (√3)²)
→ 3(√6 - √3)/(6-3)
→ (√6 - √3)
Now rationalize 3rd fraction, by multiplying (√6 - √2), in both Numerator & Denominator,
→ 4√3(√6 - √2)/((√6)² - (√2)²)
→ 4√3(√6 - √2)/(6 - 2)
→ 4(√18 - √6)/4
→ (3√2 - √6)
Finally, (Fraction 1) + (Fraction 2 - (Fraction 3), we get:
→ (3√2 - 2√3) + (√6 - √3) - (3√2 - √6)
→ -3√3 + 2√6
→ (2√6 - 3√3)
(if there is some error in calculation, please forgive me and comment below, But this is the correct Process).
Thankyou!!!
→√6(√2 - √3)/((√2)² - (√3)²)
→ (√12 - √18)/(-1)
→ -(2√3 - 3√2)
→ (3√2 - 2√3)
Now rationalize 2nd fraction, by multiplying (√6 - √3) in both Numerator & Denominator, we get:
→ 3(√6 - √3)/ ((√6)² - (√3)²)
→ 3(√6 - √3)/(6-3)
→ (√6 - √3)
Now rationalize 3rd fraction, by multiplying (√6 - √2), in both Numerator & Denominator,
→ 4√3(√6 - √2)/((√6)² - (√2)²)
→ 4√3(√6 - √2)/(6 - 2)
→ 4(√18 - √6)/4
→ (3√2 - √6)
Finally, (Fraction 1) + (Fraction 2 - (Fraction 3), we get:
→ (3√2 - 2√3) + (√6 - √3) - (3√2 - √6)
→ -3√3 + 2√6
→ (2√6 - 3√3)
(if there is some error in calculation, please forgive me and comment below, But this is the correct Process).
Thankyou!!!
Raja395:
GOOD NIGHT to all.
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