Question

plz plz tell this question step by step ​

Answer 1

hey buddy it is ur answer

Answer 2

$\bold{Solution:}$

$\underline{Given,}$

(x + 2)^3 + (x-2)^3

$\boxed{(x+y)^3=x^3+y^3+3xy(x+y)}$

【and】

$\boxed{(x-y)^3=x^3-y^3-3xy(x-y)}$

substituting values,

(x+2)^3 = x^3 + 8 + 3(2)(x){x+2}

= x^3+ 8 + 6x{x+2}

= x^3 +8 + 6x^2 + 12x ...........(i)

Similarly,

(x -2)^3 = x^3 -8 -3(2)(x){x-2}

= x^3 - 8 -6x { x-2}

= x^3 -8 - 6x^2 + 12x .............(ii)

Adding (i) and (ii)

X^3+8 +6x^2 + 12x + x^3-8 -6x^2+12x

=> 2x^3 + 24x

$\boxed{Solution=2x^3+24x}$