Question

Plz prove the above
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Answer 1

Step-by-step explanation:

1+cosA+sinA/1+cosA-sinA

devide cosA in both numerator & denominator

secA+1+tanA/secA+1-tanA

=(secA+tanA)+(sec²A-tan²A)/ secA-tanA+1

=(secA+tanA)(1+secA-tanA)/secA-tanA+1

=secA+tanA

=(1+sinA)/cosA