Plz prove the triangle .....
I will mark u as brainliest. ⁸
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- Since PQ is parellel to BC, ∆APQ is similar to ∆ABC.
- Further PQ divides the ∆ABC into two parts of equal areas ∆ABC / ∆APQ =2/1
- But ∆ABC /∆APQ = (AB /AP)^2=2/1
- AB/AP = √2/1
- AB /(AB-AP)=√2/(√2-1)
- AB/BP=√2/(√2-1)=BP/AB=(√2-1)/√2.
- So,PB√2=AB(√2-1).
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