Math, asked by hellboy9090, 1 year ago

plz prove this question

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Answered by Anonymous
0
Answer:

Step-by-step explanation:

Heya!!

( 1 - Sin A ) × ( 1 + Sin A )
_________________
Cos² A

=>

1² - Sin² A
______
Cos ² A

=>

1 - Sin² A
_______ = 1
1 - Sin² A

Becoz Cos ² A = 1 - Sin² A

hellboy9090: Bro where is SecA
Anonymous: Sec A = 1/ Cos A
Anonymous: that's y i wrote there Cos²A
Answered by rupali8153gmailcom2
2

sec(a)( \sec(a)  +  \tan(a)  -  \sin(a) sec(a) \\  -  \sin(a)  \tan(a)


 \sec(a)  (\frac1{cos}   +   \frac{ \sin(a) }{ \cos( a) }  -  \frac{ \sin(a) }{ \cos(a) }  -  \frac{ { \sin(a) }^{2} }{ \cos(a) }


 \frac{1}{ \cos(a) } (1 +  \sin(a)  -  \sin(a)  -  { \sin(a) }^{2}  \div  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \cos(a)



 \frac{1}{ \cos( a) }  \times  { \frac{ \cos(a) }{ \cos(a) } }^{2}





 = 1



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