Math, asked by vishal25505, 8 months ago

PLZ PROVE THIS QUESTION

I WILL DEFINITELY MARK AS BRAINLIEST....PLZ ......

DON'T GIVE NON-USEFUL ANS......PLZ​​

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Answers

Answered by happy271
2

Answer:hi friend mark me the brainiest plssssssss I am new here. Help me plssssssss. The answer is I have given in the below pls see it.

Step-by-step explanation:OK answer is 1/sin6. Plssssssss mark me brainiest. Make me brainiest fastttttttttt. Plssssssss.

Answered by polagokul
1

hey there !!

from LHS

(1 + 1/tan² θ ) (1 + 1/cot²θ )

=> ( 1 + cot² θ ) (1 + tan² θ )

=> (1 + cos² θ / sin² θ ) ( 1 + sin² θ/ cos² θ )

=> ( sin² θ + cos² θ/sin²θ ) ( cos² θ + sin² θ /cos²θ )

=>( 1/sin²θ ) ( 1/cos²θ )

=> 1/sin²θ×cos²θ

=> 1/sin²θ (1 - sin² θ)

=> 1/sin²θ - sin²θ= RHS prooved .

Hope It Helps!!!!!

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