Math, asked by kavyakindre, 2 months ago

Plz provide me the answer as Early as possible And plz provide answer.​

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Answers

Answered by amitsharma777222999
0

Answer:

1+sin@+cos@/1-sin@+cos@

=(1+(sin@+cos@))^2/(1+cos@)^2-sin^2@(multiply numerator and denominator by 1+sin@+cos@

=1+sin^2@+cos^2@+2sin@+2sin@cos@+2cos@/1+cos^2@+2cos@-sin^2@

=2(1+sin@)+2cos@(1+sin@)/1+cos^2@+2cos@-1+cos^2@

=(1+sin@)(1+cos@)/cos@(1+cos@)

=1+sin@/cos@

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