Question

Plz provide the solution

Answer 1

A well is dug with 14m diameter and a depth of 10m. The earth taken out is spread evely on a plot of land 100m long and 7 m wide. We have to find the height of the platform formed by earth.

So,

The radius of the well is 7m and it's depth is 10m.

It can be considered as a cylinder having a radius of 7m and a height of 10m .

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{7 \: m}}\put(9,17.5){\sf{10 \: m}}\end{picture}$

Volume of the cylinder is equivalent to the volume of earth taken out of the well

>> πr²h

>> (22/7) × 7 × 7 × 10

>> 22 × 7 × 10

>> 1540 m³

When this is evenly spread on a plot of land having dimensions 100m by 7 m

The surface area of the plot of land

>> (100m)(7m)

>> 700m²

Height of platform formed by the earth :

>> (1540m³/700m²)

>> 2.2m

Answer : The height of the platform formed by the earth is 2.2 m

$\boxed{\begin{minipage}{6.2 cm}\bigstar \:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{minipage}}$

Answer 2

Answer:

pls come back to the link