plz Q no 12 solve quickly its urgent
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(a) 1 mole of silver weighs 108 gms and has
6.022×10^23 atoms of silver. no.of moles in 5.4 gm of silver=5.4/108=0.05 moles so no. of atoms of silver=0.05×6.022×10^23=31.110×10^21=3.111×10^22 atoms .
(b) 1mole of magnesium weighs 27 gms and has 6.022×10^23 atoms of magnesium .So in2 gms of magnesium, we have 2/27×(6.022×10^23)=4.444×10^22 atoms approximately.
(c) One mole of diamond weighs 12 gms as it is an allotropic form of carbon only and has 6.022×10^23
atoms of carbon .So in 6 gms of diamond we have 6.022×10^23/2= 3.011×10^23 atoms of diamond .
6.022×10^23 atoms of silver. no.of moles in 5.4 gm of silver=5.4/108=0.05 moles so no. of atoms of silver=0.05×6.022×10^23=31.110×10^21=3.111×10^22 atoms .
(b) 1mole of magnesium weighs 27 gms and has 6.022×10^23 atoms of magnesium .So in2 gms of magnesium, we have 2/27×(6.022×10^23)=4.444×10^22 atoms approximately.
(c) One mole of diamond weighs 12 gms as it is an allotropic form of carbon only and has 6.022×10^23
atoms of carbon .So in 6 gms of diamond we have 6.022×10^23/2= 3.011×10^23 atoms of diamond .
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