Question

plz qnswer question number 3​

Answer 1

the solution of your question is in the above image.

Answer 2

$\tan( \alpha ) = \frac{4}{3}$

$\sin( \alpha ) = \frac{4}{5 }$

$\sqrt{ \frac{1 - \sin( \alpha ) }{1 + \sin( \alpha ) } } =$

$\sqrt{ \frac{1 - \frac{4}{5} }{1 + \frac{4}{5} } } = \sqrt{ \frac{5 - 4}{5 + 4} } = \sqrt{ \frac{1}{9} } = \frac{1}{3}$