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We know that Dividend = Divisor * Quotient + Remainder. ------ (1)
Here,
Dividend = 2x^3 + 4x^2 + 5x + 7
Divisor = g(x)
Quotient = 2x
Remainder = 7 - 5x.
Substitute all in (1), we get
= > 2x^3 + 4x^2 + 5x + 7 = g(x) * 2x + 7 - 5x
= > 2x^3 + 4x^2 + 5x + 7 - 7 + 5x = g(x) * 2x
= > 2x^3 + 4x^2 + 10x = g(x) * 2x
= > g(x) = (2x^3 + 4x^2 + 10x)/2x
x^2 + 2x + 5
-----------------------------
2x) 2x^3 + 4x^2 + 10x
2x^3
--------------------------------
4x^2 + 10x
4x^2
---------------------------------
10x
10x
--------------------------------------
0
Therefore g(x) = x^2 + 2x + 5.
Hope this helps!
Here,
Dividend = 2x^3 + 4x^2 + 5x + 7
Divisor = g(x)
Quotient = 2x
Remainder = 7 - 5x.
Substitute all in (1), we get
= > 2x^3 + 4x^2 + 5x + 7 = g(x) * 2x + 7 - 5x
= > 2x^3 + 4x^2 + 5x + 7 - 7 + 5x = g(x) * 2x
= > 2x^3 + 4x^2 + 10x = g(x) * 2x
= > g(x) = (2x^3 + 4x^2 + 10x)/2x
x^2 + 2x + 5
-----------------------------
2x) 2x^3 + 4x^2 + 10x
2x^3
--------------------------------
4x^2 + 10x
4x^2
---------------------------------
10x
10x
--------------------------------------
0
Therefore g(x) = x^2 + 2x + 5.
Hope this helps!
siddhartharao77:
:-)
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