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C is the answer for above question
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(C ) (ii) (iii) and (v) are the correct properties and the equipotential surface for the given field are planes parallel to y-z axis.
Explanation:
- equipotential surface are the planes which are spaced equally and perpendicular to the existing electric field.
- these surfaces can never intersect as they are parallel to each other and equally spaced.
- as electric field lines are always perpendicular to equipotential surface so the work done is always zero i.e no work is done to carry a charge on an equipotential surface.
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