Question

Plz refer to question attached and Please dont spam ,answer this

Answer 1

Answer here

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In ∆DBC :-

Tanθ =>P/B

Tanθ =>PB/BC =>10/BC (eq1)

Now ,in ∆ABC :-

Tanθ=>P/B

Tan2θ=>AB/BC

=>30/BC =>2Tanθ/1-Tanθ

=>2(10/BC)/1-100/BC^2

=>30/BC =>20 x BC /BC^2-100

=>30BC^2-3000=>20BC^2

=>10BC^2=>3000

=>BC^2=>300

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BC =>10√3=>10 x 1.732 =>17.32

hope it helps ❤mark brainliest

Answer 2

Explanation:

Answer in the attachment