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Let p(x) = x³ - 10x² + ax + b
p(x) would be a factor of (x-1) if p(1) = 0
so, p(1) = 0
so, (1)³ - 10(1)² + a(1) + b =0
so, 1-10 + a + b = 0
so, a + b = 9 ...............................(1)
Similarly, p(2) = 0
(2)³ -10(2)² + a(2) + b = 0
8 - 40 +2a + b = 0
so, 2a + b = 32 ...........................................(2)
BY subtracting Eqn (1) from (2)
2a + b = 32
a + b = 9
a = 23 and b = -14
p(x) would be a factor of (x-1) if p(1) = 0
so, p(1) = 0
so, (1)³ - 10(1)² + a(1) + b =0
so, 1-10 + a + b = 0
so, a + b = 9 ...............................(1)
Similarly, p(2) = 0
(2)³ -10(2)² + a(2) + b = 0
8 - 40 +2a + b = 0
so, 2a + b = 32 ...........................................(2)
BY subtracting Eqn (1) from (2)
2a + b = 32
a + b = 9
a = 23 and b = -14
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