Question

plz reply what is the answer of this question

Answer 1

Answer:

Step-by-step explanation:

PQ=PR   ............given

PS=PT     ..........given

PQ-PS=PR-PT

QS=TR

now in ΔQSR and ΔRQT

QS=TR      proved above

∠SQR=∠TRQ       as PQ=PR angle opp to equal sides are equal

QR=QR               common side

⇒ΔSQR=ΔTRQ

⇒QT=RS         cpct

HENCE PROVED