Math, asked by shabanap2288, 10 hours ago

plz say correct answer if you will give wrong answer i will report you​

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Answers

Answered by prabhjotsingh34353
1

Answer:

here is your solution See

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Answered by shrirampawar249
0

Answer:

 \frac{2}{ \sqrt{5} +  \sqrt{3}  } +  \frac{1}{ \sqrt{3} +  \sqrt{2}  }   -  \frac{3}{ \sqrt{5}  +  \sqrt{2} }  \\  \frac{2( \sqrt{5} -  \sqrt{3})  }{( \sqrt{5}  +  \sqrt{3} )( \sqrt{5} -  \sqrt{3})  }  +  \frac{1( \sqrt{3}  -  \sqrt{2} }{( \sqrt{3} +  \sqrt{2}  )( \sqrt{3}  -  \sqrt{2} )}  -  \frac{3( \sqrt{5} -  \sqrt{2} ) }{( \sqrt{5} +  \sqrt{2})( \sqrt{5}  -  \sqrt{2})   }  \\  \frac{2 \sqrt{5} - 2 \sqrt{3}  }{5 - 3}  +  \frac{ \sqrt{3}  -  \sqrt{2} }{3 - 2}   -  \frac{3( \sqrt{5}  -  \sqrt{2}) }{5 - 2}  \\  \frac{2( \sqrt{5} -  \sqrt{3})  }{2}  -  \frac{3( \sqrt{5}  -  \sqrt{2}) }{3}  +  \sqrt{3}  -  \sqrt{2}  \\  \sqrt{5}  -  \sqrt{3}  -  \sqrt{5}  +  \sqrt{2}  +  \sqrt{3}  -  \sqrt{2}  \\  = 0

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