Math, asked by madhur2110, 11 months ago

plz see the attached que and help me in the solution​

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Answers

Answered by avikshitchanda
1

Answer:

25/81

HERE IS YOUR ANSWER

IN TRIANGLE ABC,

DE IS PARALLEL TO BC

SO,TRIANGLE ADE IS SIMILAR TO TRIANGLE ABC

SO,AD/AB=DE/BC    [CPCT]

5X/9X=DE/BC

DE/BC=5/9 .........[1]

NOW IN TRIANGLE DFE AND CFB

ANGLE  EDF =ANGLE   BCF     [ALTERNATE INTERIOR ANGLE]

ANGLE   DFE= ANGLE   CFB            [VERTICALLY OPP ANGLES]

SO, TRIANGLE DFE IS SIMILAR TO TRIANGLE CFB      [AA RULE]

=>AREA[DFE]/AREA[CFB]=[DE/BC]^2

=>[5/9]^2

=>25/81

I HOPE THIS HELPS PLZ MARKIT AS THE BRAINLIEST

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