plz see the attached que and help me in the solution
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25/81
HERE IS YOUR ANSWER
IN TRIANGLE ABC,
DE IS PARALLEL TO BC
SO,TRIANGLE ADE IS SIMILAR TO TRIANGLE ABC
SO,AD/AB=DE/BC [CPCT]
5X/9X=DE/BC
DE/BC=5/9 .........[1]
NOW IN TRIANGLE DFE AND CFB
ANGLE EDF =ANGLE BCF [ALTERNATE INTERIOR ANGLE]
ANGLE DFE= ANGLE CFB [VERTICALLY OPP ANGLES]
SO, TRIANGLE DFE IS SIMILAR TO TRIANGLE CFB [AA RULE]
=>AREA[DFE]/AREA[CFB]=[DE/BC]^2
=>[5/9]^2
=>25/81
I HOPE THIS HELPS PLZ MARKIT AS THE BRAINLIEST
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