plz see the questionin the picture
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1
Answer:
<ade=70 (alt. int. angles)
in triangle dre
70+40+<dre=180 (asp)
=> <dre=70
<dre+<are=180 (linear pair)
=> <are= 110
hope this clarifys your doubt
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0
Answer:
AB||DE,AD is a transversal
angle BAD= angle ADE=70°(alternate interior angle)
angle RDE+angle DER=angle ARE(exterior angle property)
70°+40°=110°
therefore, angle ARE=110°
angle ARE+angle DRE=180°(linear pair)
110°+angle DRE=180°
angle DRE=180°-110°=70°
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