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here, u (initial velocity)= 18km/h = 18000/3600m/s = 5m/s
v (final velocity) = 36km/h = 36000/3600 = 10m/s
we know that a = (v-u) / t
a = 10-5 /5
a = 5/5 = 1m/s^2
therefore distance= ut + 1/2×at^2
s= 5×5 + 1/2 ×1×25
=25+ 25/2
= (50+25)/2
= 75/2
= 37.5 m
v (final velocity) = 36km/h = 36000/3600 = 10m/s
we know that a = (v-u) / t
a = 10-5 /5
a = 5/5 = 1m/s^2
therefore distance= ut + 1/2×at^2
s= 5×5 + 1/2 ×1×25
=25+ 25/2
= (50+25)/2
= 75/2
= 37.5 m
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