Question

plz send me answer fast

Answer 1

In ∆KNO and ∆KML
$\angle N$=$\angle M$
$\angle K$= $\angle K$

So ∆KNO similar to ∆KML

SO,
$\frac {KN} {KM}$ = $\frac {ON}{LM}$

$\frac {c} {c+b}$= $\frac {x}{a}$

x= $\frac {ac}{c+b}$