Question

Plz send me any one of the solution guyzzz​

Answer 1

Answer:

Hey frnd...ur answer here

Step-by-step explanation:

Thnkss

Answer 2

Answer:

LHS

(cotA - cosA )/(cotA + cosA)

cosA(1/sinA - 1)/cosA(1/sinA + 1)

on dividing sinA in Above and below we get

(cosecA - 1)/(cosecA + 1)

so

LHS = RHS

LHS

(tanA + SinA )/(tanA - sinA)

sinA(secA +1)/sinA(secA - 1)

(secA + 1)/(secA - 1)

so

LHS = RHS