Question

plz send me the solution ​

Answer 1

Answer:

The answer is option (b)

Answer 2

here your answer.

a). net accelerating force = 40000-5000

= 35000N

b). acceleration: force/mass =

35000 / ( 8000 + 5×2000) = 1.94 m/s²

c). the force of wagon 1 on wagon 2.

imagine the wagon 1 and engine detached,and a force p is included to account for the detachment.

Then the net force acting, p which is acting from wagon 2 onto 1 and is same as acting from 1 to 2.

p = ma = (8000 + 2000) (1.94) = 19400 N.

Hence the force of wagon 1 on 2 is 19400 N.

I hope it will helps you.

best of luck for your exams.

thank you..!!