Question

plz send solution i am saketh​

Answer 1

This answer will help you

Answer 2

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HEYA MATE

$\tan( \alpha ) = \frac{p}{h} = \frac{4}{3}$



BY PYTHAGORAS THEOREM


H^2=P^2+B^2



${h}^{2} = {4}^{2} + {3}^{2} \\ \: \: \: \: = 16 + 9 \\ \: \: \: \: = 25 \\ \\ {h}^{2} = 25 \\ h = \sqrt{25} \\ h = 5cm$



$\sin( \alpha ) = \frac{p}{h} = \frac{4}{5} \\ \\ \cos( \alpha ) = \frac{b}{h} = \frac{3}{5}$



$\sin( \alpha ) + \cos( \alpha ) = \frac{4}{5} + \frac{3}{5} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{7}{5}$


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HOPE IT HELPS MATE