Question

plz send the answer​

Answer 1

✔ Given :

• Length = 16 cm

• Area = 192 sq.cm

✔ To Find :

• The digonal of a reactangle = ?

✔ Solution :

Area = Length × Breadth

➪192 = 16 × BC

➪BC = 192/16

➪BC = 12 cm

☢According to Pythagoras theorem :

In ∆ABC,

➪ AB² + BC² = AC²

➪ (16)² + (12)² = AC²

➪ 256 + 144 = AC²

➪ AC² = 400

➪ AC = 20 cm.

Hence, "the length of the diagonal of the reactangle is 20 cm".

Answer 2

Question

Find the diagonal of a rectangle whose length in 16cm and area is 192 sq.m

Answer:

• Diagonal = 20cm

Step-by-step explanation

♤ Given :

• Length = 16cm

• Area = 192 cm^2

♤ To Find :

• Breadth = ?

• Diagonal =?

♤ Formula and Theorem used :

• Area = length × breadth

• Pythagorus theorem. [ (length)^2 + (breadth)^2 = (diagonal)^2

♤ Procedure :

《》 Finding breadth :

$\mathsf {length \times breadth = area }$

$\implies16 \times x = 192$

$\implies \: x = \dfrac{192}{16}$

$\implies \: x = 12cm$

${{ \huge{\boxed{ \bold {breadth = 12cm }}}}}$

《》 Finding diagonal:

$\sf \: {(diagonal)}^{2} + {(breadth)}^{2} = {(diagona)}^{2}$

${16}^{2} + {12}^{2} = 400$

$\sf \: diagonal = \sqrt{400}$

$\sf \: diagonal = 20cm$