Math, asked by knvenkateshvenkatesh, 10 months ago

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Answered by MokshHanda
0

Area of the trapezium = h/2 (a + b)

where a and b are the parallel sides

h = perpendicular distance between the parallel sides

Area of the trapezium ABCD = AB/2 (AD + BC)

24.5 = (AB/2) (10 + 4)

49 = AB (14)

AB = 3.5 cm

Radius of the quadrant of the circle = AB = 3.5 cm

Area of the quadrant of the circle = 1/4πr²

= 1/4 x 22/7 x 3.5 x 3.5

= 9.625 cm2

Area of the shaded region = Area of the trapezium - Area of the quadrant of the circle

= 24.5 - 9.625

= 14.875 cm2

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