Question

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Answer 1

${(3x - \frac{1}{3x} )}^{2} - (3x + \frac{1}{3x} )(3 - \frac{1}{3x} ) \\ = ( {(3x)}^{2} - 2 \times 3x \times \frac{1}{3x} + {( \frac{1}{3x} )}^{2} ) - ( {(3x)}^{2} - {( \frac{1}{3x} )}^{2} ) \\ = {9x}^{2} - 2 + \frac{1}{ {9x}^{2} } - {9x}^{2} + \frac{1 }{ {9x}^{2} } \\ = \frac{1}{ {9x}^{2} } + \frac{1}{ {9x}^{2} } - 2 \\ = \frac{1 + 1 - 18 {x}^{2} }{ {9x}^{2} } \\ = \frac{2 - {18x}^{2} }{ {9x}^{2} }$