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Step-by-step explanation:
Let F,B,C be the sets of students who received medals in football, basketball, and cricket respectively.
n(F)=38
n(B)=15
n(C)=20
n(F∪B∪C)=58
n(F∩B∩C)=3
We know, n(F∪B∪C)=n(F)+n(B)+n(C)−n(F∩B)−n(B∩C)−n(F∩C)+n(F∩B∩C)
n(F∩B)+n(B∩C)+n(C∩F)=73−58+3=18
the number of students who received medals in exactly two of the three
sports is,
n(F∩B)+n(B∩C)+n(C∩F)−3×n(F∩B∩C)=18−9=9
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