Question

Plz slove this 4 questions​

Answer 1

Answer:

$6)angal acb = 50$

$5)x = y = 75$

$7)angle \: bap = 40 \: \: acb = 60$

Answer 2

$\huge \blue {ANSWER}$

1)IF AB=AC

THEN ∠C=∠B

NOW,A.C.Q

$30+x+x=>180$

$2x=>180-30$

$x=>150/2$

$x=>75$

$So,∠A=>30°$

$∠B=>75°$

$∠C=>75°$ ANSWER

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2)BY USING PROPERTY =>SUM OF 2 OPPOSITE INTERIOR ANGLES IS EQUAL TO ONE EXTERIOR ANGLE

$80+x=>130°$

$x=>130-80$

$x=>50$

$So,∠A=>50°$ ANSWER

BY USING PROPERTY

$∠ACB+130°=>180°$

$∠ACB=>180°-130°$

$∠ACB=>50°$ ANSWER

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$3)(i)∠B+∠P+∠BAP=>180°$

$60°+90°+x=>180°$

$150°+x=>180°$

$x=>180°-150°$

$x=>30°$

$SO, DIVIDE 30/2=>15°$ ANSWER

(ii)IF AB=AC

:. ∠C=∠B

$IF ∠B=60°$

$∠C=60°$ ANSWER

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$4)•110+x=>180°$

$x=>180-110$

$x=>70°$ ANSWER

•BY USING PROPERTY =>SUM OF 2 OPPOSITE INTERIOR ANGLES IS EQUAL TO ONE EXTERIOR ANGLE

$40+y=>110$

$y=>110-40$

$y=>70°$ ANSWER

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HOPE SO IT IS HELPFUL..❣️✌️..