Question

Plz slove this first brinliest

Answer 1

$\Large \bullet~~ \mathfrak \green {Question:-}$

Question is provided in the attachment.

$\Large \bullet ~~\mathfrak \green {Solution:-}$

✍️ Given :-

∆ABC is an isosceles triangle [AB=AC] ; D, E and F are the midpoints of sides AB, BC and AC.

✍️ To prove :-

We have to prove that ∆DBE is congruent to ∆FCE.

✍️ Proof :-

In ∆DBE and ∆FCE :

$\pink \mapsto \sf BC = EC \: (E~is~the~midpoint~of~BC)$

$\pink \mapsto \sf < DBE=~ < FCE \: (Angles~opposite~to \\ \sf ~~~~equal~sides~are~equal)$

$\pink \mapsto \sf DB=FC~(D~and~F~are~the~midpoints \\ \sf of~equal~sides~AB,AC)$

$\sf {\blue {\therefore \triangle DBE~and~\triangle FCE~are~congruent~to~each}} \\ \sf {\blue {other~by~SAS~congruence~rule.}}$

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@Sita05