Math, asked by gamezoid76, 8 months ago

plz slove this question​

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Answered by keerthanasre
1

Answer:

sin^2∅+cos^2∅+tan^2∅+cot^2∅+sec^2∅+cosec^2∅

= 1+sin^2∅/cos^2∅+cos^2∅/sin^2∅+1/cos^2∅+1/sin^2∅

= 1+ (sin^2∅+1)/cos^2∅ + (cos^2∅+1)/sin^2∅

= 1+ (sin^4∅+cos^4∅)/sin^2∅cos^2∅

= 1+ ((sin^2∅+cos^2∅)^2 - 2sin^2∅cos^2∅)/sin^2∅cos^2∅

= 1+ sec^2∅cosec^2∅-2

= sec^2∅cosec^2∅ -1

Kindly check the question..I am unable to solve furthur.

Sorry for the inconvenience

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