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Answer:
a°=48°
Step-by-step explanation:
the sum of the interior angles of the Pentagon is 540°
a°+(a+20°)+(a+40°)+(a+60°)+(a+80°)=540
5a°+ 20+40+60+80 =540
5a°+200=540
5a°=540-200
5a°=340
a°=340/5
a°=68°
hence,the smallest angle of the Pentagon is a°=68°
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